I was running the program
#include<stdio.h>
#include <unistd.h>
main()
{
pid_t pid, ppid;
printf("Hello World1\n");
pid=fork();
if(pid==0)
{
printf("I am the child\n");
printf("The PID of child is %d\n",getpid());
printf("The PID of parent of child is %d\n",getppid());
}
else
{
printf("I am the parent\n");
printf("The PID of parent is %d\n",getpid());
printf("The PID of parent of parent is %d\n",getppid());
}
}
THe output I got was.
$ ./a.out
Hello World1
I am the parent
The PID of parent is 3071
The PID of parent of parent is 2456
I am the child
The PID of child is 3072
The PID of parent of child is 1
I couldnt understand the line
The PID of parent of child is 1
It should have been 3071?
Parent process doesn't wait (by means of wait(2) ) for the child process to complete. So, if parent exits before the child (it becomes an orphan process), then child process will be re-parented (adopted) to init process whose process ID is usually 1. Thus the child process says its parent process ID is 1.
The getpid() function returns the process ID of the calling process. The getpgrp() function returns the process group ID of the calling process. The getppid() function returns the parent process ID of the calling process.
The child's pid is always 0 in its own environment. The parent process is the one that sees the real pid.
getpid() : returns the process ID of the calling process. This is often used by routines that generate unique temporary filenames.
Because parent process is finished by the time the child asks for its parent's pid.
When a process finishes, all its children are reassigned as children of the init process, which pid is 1.
Try using wait()
in parent's code to wait for the child to execute. It should then work as you expect.
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