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Why doesn't TypeSynonymInstances allow partially applied type synonyms to be used in instance heads?

Tags:

haskell

I know that TypeSynomymInstances only allows fully applied type synonyms to be used in instance heads, but it seems like it would be handy if I could use paritally applied type synonyms to be used as well.

For instance:

class Example e where
  thingy :: a -> b -> e a b

-- legit, but awkward
newtype FuncWrapper e a b = FuncWrapper { ap :: a -> e a b }
instance (Example e) => Example (FuncWrapper e) where
  thingy _ = FuncWrapper . flip thingy
funcWrapperUse :: (Example e) => e Int String
funcWrapperUse = thingy 1 "two" `ap` 3 `ap` 4 `ap` 5

-- not legal, but a little easier to use
type FuncSynonym e a b = a -> e a b
instance (Example e) => Example (FuncSynonym e) where
  thingy _ = flip thingy
funcSynonymUse :: (Example e) => e Int String
funcSynonymUse = thingy 1 "two" 3 4 5
like image 387
rampion Avatar asked Feb 07 '11 14:02

rampion


2 Answers

Partially applied type synonyms are not allowed in Haskell at all. A partially applied synonym is effectively a function whose inputs are the un-applied types and whose output is a type. For example, here is an encoding of boolean logic:

type True x y = x
type False x y = y
type Not b x y = b y x
type And b1 b2 x y = b1 (b2 x y) y
type Or b1 b2 x y = b1 x (b2 x y)

To decide whether two partially applied type synonyms are equal, the type checker would have to decide whether functions are equal. This is a hard problem, and in general it is undecidable.

like image 140
Heatsink Avatar answered Nov 05 '22 15:11

Heatsink


Another issue with allowing partially applied type synonyms is that they would make type inference and instance selection essentially impossible. For example, suppose in the context of some program I wanted to use thingy at the type Int -> String -> Int -> (Int, String). thingy has type forall a b e. a -> b -> e a b, so we can unify a with Int and b with String, but if e is allowed to be a partially applied type synonym, we could have

e = FuncSynonym (,)

or

e = FuncSynonym' Int (,) where type FuncSynonym' x f a b = x -> f a b

or even

e = Const2 (Int -> (Int, String)) where Const2 a x y = a

The problem of type inference would become even worse than deciding equality of functions; it would require considering all functions with specified output on a particular input, or similar more complicated problems (imagine simply trying to unify a b with Int).

like image 33
Reid Barton Avatar answered Nov 05 '22 17:11

Reid Barton