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Why doesn't a nested reference to an array coerce to a slice?

I read What are Rust's exact auto-dereferencing rules? from beginning to end, but I still have a question about the coercion from array to slice.

Let us think about the following code:

let arr: &[i32; 5] = &&&[1, 2, 3, 4, 5];
// let arr: &[i32] = &&&[1, 2, 3, 4, 5]; // Error; expected slice, found reference

I would expect that &&&[1, 2, 3, 4, 5] has the type, &&&[i32; 5] and dereferences to &&[i32; 5] => &[i32; 5] => &[i32; 5] => &[i32], but the result is different from what I expected.

I tried to run the following code:

let arr: &&&[i32; 5] = &&&[1, 2, 3, 4, 5];
let n = arr.first().unwrap(); // 1

That's the correct code. The type of arr is coerced to &&&[i32; 5] => &&[i32; 5] => &[i32; 5] => &[i32] and matches to the first argument of first in slice, &self.

What's the condition that arrays coerce to slices? I don't understand the difference between the former and the latter code.

I also checked the documentation in the source code, and guess that the above question has something to do with the sentence cited below;

However we sometimes do other adjustments and coercions along the way, in particular unsizing (e.g., converting from [T; n] to [T]).`

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Kenta Nakajima Avatar asked Nov 11 '17 12:11

Kenta Nakajima


1 Answers

This kind of coercion is intended to work, but not implemented.

Arrays do not implement Deref, so the coercion &[T; n] -> &[T] is not a deref coercion and does not work in quite the same way as one. Instead, it's called an "unsized coercion" because it turns a sized type ([T; n]) into an unsized one ([T]).

That said, the language reference (which is not normative and may be outdated, but bear with me) lists the possible coercions, including the following (emphasis added):

  • T_1 to T_3 where T_1 coerces to T_2 and T_2 coerces to T_3 (transitive case)

    Note that this is not fully supported yet.

  • &T or &mut T to &U if T implements Deref<Target = U>.

  • TyCtor(T) to TyCtor(U), where TyCtor(T) is one of

    • &T
    • &mut T
    • *const T
    • *mut T
    • Box<T>

    and where U can be obtained from T by unsized coercion.

The last bullet, unsized coercion, is what allows &[T; n] to coerce to &[T]. Notably, this only describes one layer of referencing; it doesn't cover the &&[T; n] -> &[T] case (for which we also need Deref coercion).

Back to your non-working example:

let arr: &[i32] = &&&[1, 2, 3, 4, 5];

The intended coercion is &&&[i32; 5] -> &[i32]. We can work out how this coercion ought to work:

  1. &[i32; 5] coerces to &[i32] by unsizing;
  2. &&[i32; 5] coerces to &[i32; 5] by Deref;
  3. therefore, &&[i32; 5] coerces to &[i32] by transitivity.
  4. &&&[i32; 5] coerces to &&[i32; 5] by Deref;
  5. therefore, &&&[i32; 5] coerces to &[i32] by transitivity.

But it doesn't. The quote above hints at why: under the transitive case, it says "Note that this is not fully supported yet". As far as I can tell, according to issue #18602, "not fully supported" is a hedge; it would be more accurate to say "unimplemented". So, for now, coercion via transitivity is not possible at all. Apparently this issue is not a high priority, probably because sized arrays aren't very common. (I suspect this might become a more common complaint when const generics land, since that may make arrays more useful.)

So why does arr.first() work? Well, the "auto-dereferencing rules" used to find methods invoked with the . (dot) operator are different from the coercion rules. Autoderef is similar to manually dereferencing any number of times until you get something (that can be coerced to a type) with the given method. This means you don't need transitive coercion to find method calls through autoderef.


Further reading

RFC #401 describes intended semantics of most coercions, but has never been fully implemented. Issue #18602 tracks the status of transitive coercion.

The Rustonomicon also has a chapter on coercions and appears to agree with the reference book.

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trent Avatar answered Oct 19 '22 23:10

trent