I hope the question is correct, so let's give you an example. Imagine the following generic method:
public abstract class Base : IDisposable
{
public static IEnumerable<T> GetList<T>()
where T : Base
{
// To ensure T inherits from Base.
if (typeof(T) is Base)
throw new NotSupportedException();
// ...
}
}
According to the MSDN the keyword where
restricts the type parameter T
to be of type Base
or to inherit from this class.
[...] a where clause can include a base class constraint, which states that a type must have the specified class as a base class (or be that class itself) in order to be used as a type argument for that generic type.
Also this code does compile:
public static T GetFirst()
where T : Base
{
// Call GetList explicitly using Base as type parameter.
return (T)GetList<Base>().First();
}
So when following the last code typeof(T)
should return Base
, shouldn't it? Why does Visual Studio then prints this warning to me?
warning CS0184: The given expression is never of the provided ('Demo.Base') type.
typeof(whatever)
always returns an instance of type Type
. Type
doesn't derive from Base
.
What you want is this:
if(typeof(T) == typeof(Base))
throw new NotSupportedException("Please specify a type derived from Base");
Something that looks like it is the same is this:
if(variableOfTypeT is Base)
But that has a different meaning.
The first statement (with typeof(Base)
) only is true
if T
is Base
. It will be false
for any type derived from Base
.
The second statement (variableOfTypeT is Base
) is always true
in your class, because any class derived from Base
will return true
for a check for its base class.
That's not how you check inheritance.
typeof(T)
is of type System.Type
, it's not Base
. To see if T is derived from Base you should use the IsSubclassOf method, like this:
if(typeof(T).IsSubclassOf(typeof(Base)) ...
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