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My command is like this:
echo "12 cats" | sed 's/[0-9]+/Number/g'
(I'm using the sed in vanilla Mac)
I expect the result to be:
Number cats
However, the real result is:
12 cats
Does anyone have ideas about this? Thanks!
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Because you are using PCRE (Perl Compatible Regular Expressions) syntax and sed doesn't understand that, it uses Basic Regular Expressions (BRE) by default. It knows neither \s nor \d .
Find and replace text within a file using sed command Use Stream EDitor (sed) as follows: sed -i 's/old-text/new-text/g' input.txt. The s is the substitute command of sed for find and replace. It tells sed to find all occurrences of 'old-text' and replace with 'new-text' in a file named input.txt.
The sed command, short for stream editor, performs editing operations on text coming from standard input or a file. sed edits line-by-line and in a non-interactive way. This means that you make all of the editing decisions as you are calling the command, and sed executes the directions automatically.
+ must be backslashed to get its special meaning.
echo "12 cats" | sed 's/[0-9]\+/Number/g'
Expanding the + modifier works for me:
echo "12 cats" | sed 's/[0-9][0-9]*/Number/g'
Also, the -E switch would make the + modifier work, see choroba’s answer.
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