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I cannot redirect to another page if the code is like this:
<h:commandButton type="button" value="Enter" action="index?faces-redirect=true" >
But the redirect works if the code is:
<h:commandButton type="button" value="Enter" action="index?faces-redirect=true" >
<f:ajax />
</h:commandButton>
Could anyone explain this? Thanks!
-----------------------EDIT------------------------
The entire xhtml code for your reference:
<html xmlns="http://www.w3.org/1999/xhtml"
xmlns:h="http://java.sun.com/jsf/html"
xmlns:f="http://java.sun.com/jsf/core"
xmlns:ui="http://java.sun.com/jsf/facelets"
xmlns:p="http://primefaces.org/ui">
<h:head>
</h:head>
<h:body>
<h:form id="form">
<h:commandButton id="enterModelButton" type="button" value="Enter" action="index?faces-redirect=true" >
<f:ajax />
</h:commandButton>
</h:form>
</h:body>
</html>
901
The <h:commandButton type="button"> doesn't generate a submit button. It just generates a "dead" button without any effects, purely intented to be used for custom onclick="..." scripts and like. This is somewhat a leftover of the dark JSF 1.0/1.1 era, when it wasn't nicely possible to just use plain vanilla HTML in JSF for this kind of things.
The <f:ajax> performs the submit by ajax powers through JSF-generated onclick. It doesn't care about the button's type.
Essentially, removing type="button" and relying on its default type="submit" should fix your problem.
<h:commandButton value="Enter" action="index?faces-redirect=true" />
However, all with all, if this is the real code and you don't actually intend to invoke a bean action, then you're going in completely the wrong direction as to implementing the functional requirement of navigating to a different page by a button. You should be using <h:button> instead.
<h:button value="Enter" outcome="index" />
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