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Why does std::atomic's compare_exchange take a reference for the expected value?

Tags:

c++

c++11

atomic

What is the reason for std::atomic<T>::compare_exchange_* taking the expected value by reference, instead of taking it by value?

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Collin Dauphinee Avatar asked Nov 14 '13 19:11

Collin Dauphinee

1 Answers

compare_exchange_* changes expected to actual value if operation fails. It makes loops a bit simpler.

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zch Avatar answered Nov 08 '22 17:11

zch
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