Why does R throw the error "Error in value[3L] : no loop for break/next, jumping to top level" instead of going to the next iteration of a loop? I'm on R version 2.13.1 (2011-07-08)
for (i in seq(10)) {
tryCatch(stop(), finally=print('whoops'), error=function(e) next)
}
This problem came up because I wanted to create a different image or no image at all when plot failed. The code, using joran's approach, would look like this:
for (i in c(1,2,Inf)) {
fname = paste(sep='', 'f', i, '.png')
png(fname, width=1024, height=768)
rs <- tryCatch(plot(i), error=function(e) NULL)
if (is.null(rs)){
print("I'll create a different picture because of the error.")
}
else{
print(paste('image', fname, 'created'))
dev.off()
next
}
}
Maybe you could try :
for (i in seq(10)) {
flag <- TRUE
tryCatch(stop(), finally=print('whoops'), error=function(e) flag<<-FALSE)
if (!flag) next
}
Unfortunately, once you get inside your error
function you're no longer in a loop. There's a way you could hack around this:
for (i in seq(10)) {
delayedAssign("do.next", {next})
tryCatch(stop(), finally=print('whoops'),
error=function(e) force(do.next))
}
Though that is... well, hacky. Perhaps there is a less hacky way, but I don't see one right off.
(This works because delayedAssign
happens every loop, canceling out the efforts of force
)
EDIT
Or you could use continuations:
for (i in seq(10)) {
callCC(function(do.next) {
tryCatch(stop(), finally=print('whoops'),
error=function(e) do.next(NULL))
# Rest of loop goes here
print("Rest of loop")
})
}
EDIT
As Joris points out, you probably shouldn't actually use either of these, because they're confusing to read. But if you really want to call next
in a loop, this is how :).
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