The documentation for Python's itertools.cycle() gives a pseudo-code implementation as:
def cycle(iterable):
# cycle('ABCD') --> A B C D A B C D A B C D ...
saved = []
for element in iterable:
yield element
saved.append(element)
while saved:
for element in saved:
yield element
Below, it states: "Note, this member of the toolkit may require significant auxiliary storage (depending on the length of the iterable)."
I basically was going down this path, except I did this, which does not require creating a copy of the iterable:
def loop(iterable):
it = iterable.__iter__()
while True:
try:
yield it.next()
except StopIteration:
it = iterable.__iter__()
yield it.next()
x = {1, 2, 3}
hard_limit = 6
for i in loop(x):
if hard_limit <= 0:
break
print i
hard_limit -= 1
prints:
1
2
3
1
2
3
Yes, I realize my implementation wouldn't work for str's, but it could be made to. I'm more curious as to why it creates another copy. I have a feeling it has to do with garbage collection, but I'm not well studied in this area of Python.
Thanks!
Itertools is the Python module that contains some inbuilt functions for generating sequences using iterators. This module provides various functions that work on iterators to produce complex iterators.
The cycle() function accepts an iterable and generates an iterator, which contains all of the iterable's elements. In addition to these elements, it contains a copy of each element.
Python's Itertool is a module that provides various functions that work on iterators to produce complex iterators. This module works as a fast, memory-efficient tool that is used either by themselves or in combination to form iterator algebra.
Iterables can only be iterated over once.
You create a new iterable in your loop instead. Cycle cannot do that, it has to work with whatever you passed in. cycle
cannot simply recreate the iterable. It thus is forced to store all the elements the original iterator produces.
If you were to pass in the following generator instead, your loop()
fails:
def finite_generator(source=[3, 2, 1]):
while source:
yield source.pop()
Now your loop()
produces:
>>> hard_limit = 6
>>> for i in loop(finite_generator()):
... if hard_limit <= 0:
... break
... print i
... hard_limit -= 1
...
1
2
3
Your code would only work for sequences, for which using cycle()
would be overkill; you don't need the storage burden of cycle()
in that case. Simplify it down to:
def loop_sequence(seq):
while True:
for elem in seq:
yield elem
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