Why does non-lenient SimpleDateFormat parse dates with letters in?

Question

When I run the following code I would expect a stacktrace, but instead it looks like it ignores the faulty part of my value, why does this happen?

package test;

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;

public class Test {
  public static void main(final String[] args) {
    final String format = "dd-MM-yyyy";
    final String value = "07-02-201f";
    Date date = null;
    final SimpleDateFormat df = new SimpleDateFormat(format);
    try {
      df.setLenient(false);
      date = df.parse(value.toString());
    } catch (final ParseException e) {
      e.printStackTrace();
    }
    System.out.println(df.format(date));
  }

}

The output is:

07-02-0201

Answer 1

The documentation of DateFormat.parse (which is inherited by SimpleDateFormat) says:

The method may not use the entire text of the given string.

final String value = "07-02-201f";

In your case (201f) it was able to parse the valid string till 201, that's why its not giving you any errors.

The "Throws" section of the same method has defined as below:

ParseException - if the beginning of the specified string cannot be parsed

So if you try changing your string to

final String value = "07-02-f201";

you will get the parse exception, since the beginning of the specified string cannot be parsed.