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Is there a reason being list.append evaluating to false? Or is it just the C convention of returning 0 when successful that comes into play?
>>> u = [] >>> not u.append(6) True 
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💡 Tips: When you use . append() the original list is modified. The method does not create a copy of the list – it mutates the original list in memory.
append() will place new items in the available space. Lists are sequences that can hold different data types and Python objects, so you can use . append() to add any object to a given list. In this example, you first add an integer number, then a string, and finally a floating-point number.
Every element of the list turns to the newly appended element. For example, after 4 squares of the maze, the 4 elements in past are changed to whatever the appended element is.
Append in Python is essential to add a single item at the end of a list, array, deque, or other collection types and data structures on the go.
Most Python methods that mutate a container in-place return None -- an application of the principle of Command-query separation. (Python's always reasonably pragmatic about things, so a few mutators do return a usable value when getting it otherwise would be expensive or a mess -- the pop method is a good example of this pragmatism -- but those are definitely the exception, not the rule, and there's no reason to make append an exception).
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