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I'm looking for an efficient way to convert a series to a tuple of its index with its values.
s = pd.Series([1, 2, 3], ['a', 'b', 'c']) I want an array, list, series, some iterable:
[(1, 'a'), (2, 'b'), (3, 'c')] 
508
Creating a pandas Series from a tuple is similar to creating a Series from a list. Make the tuple which contains the required data, and then pass it to the data parameter of the series constructor.
Accessing Element from Series with Position In order to access the series element refers to the index number. Use the index operator [ ] to access an element in a series. The index must be an integer. In order to access multiple elements from a series, we use Slice operation.
The object supports both integer- and label-based indexing and provides a host of methods for performing operations involving the index. Pandas Series. index attribute is used to get or set the index labels of the given Series object.
Well it seems simply zip(s,s.index) works too!
For Python-3.x, we need to wrap it with list -
list(zip(s,s.index)) To get a tuple of tuples, use tuple() : tuple(zip(s,s.index)).
Sample run -
In [8]: s Out[8]: a 1 b 2 c 3 dtype: int64 In [9]: list(zip(s,s.index)) Out[9]: [(1, 'a'), (2, 'b'), (3, 'c')] In [10]: tuple(zip(s,s.index)) Out[10]: ((1, 'a'), (2, 'b'), (3, 'c')) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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