Why does `"%c"` exist in `printf` if `char` is converted to `int`?

Question

In C you have the "%c" and "%f" formats flags for printf- and scanf-like functions. Both of these function use variable length arguments ..., which always convert floats to doubles and chars to ints.

My question is, if this conversion occurs, why do separate flags for char and float exist? Why not just use the same flags as for int and double?

Related question:
Why does scanf() need "%lf" for doubles, when printf() is okay with just "%f"?

Answer 1

Because the way it gets printed out is different.

printf("%d \n",100); //prints 100
printf("%c \n",100); //prints d - the ascii character represented by 100