Why do I first have to strcpy() before strcat()?

Question

Why does this code produce runtime issues:

char stuff[100]; strcat(stuff,"hi "); strcat(stuff,"there"); 

but this doesn't?

char stuff[100]; strcpy(stuff,"hi "); strcat(stuff,"there"); 

Answer 1

strcat will look for the null-terminator, interpret that as the end of the string, and append the new text there, overwriting the null-terminator in the process, and writing a new null-terminator at the end of the concatenation.

char stuff[100];  // 'stuff' is uninitialized 

Where is the null terminator? stuff is uninitialized, so it might start with NUL, or it might not have NUL anywhere within it.

In C++, you can do this:

char stuff[100] = {};  // 'stuff' is initialized to all zeroes 

Now you can do strcat, because the first character of 'stuff' is the null-terminator, so it will append to the right place.

In C, you still need to initialize 'stuff', which can be done a couple of ways:

char stuff[100]; // not initialized stuff[0] = '\0'; // first character is now the null terminator,                  // so 'stuff' is effectively "" strcpy(stuff, "hi ");  // this initializes 'stuff' if it's not already.