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That is, why does this:
struct S {}; struct T { T(S& s) : s{s} {} S& s; }; int main() { S s; T t{s}; } give me a compiler error with GCC 4.7:
test.cpp: In constructor 'T::T(S&)': test.cpp:5:18: error: invalid initialization of non-const reference of type 'S&' from an rvalue of type '<brace-enclosed initializer list>' ?
To fix the error, I have to change the s{s} to s(s). Doesn't this break the, erm, uniformity of uniform initialization?
EDIT: I tried with clang, and clang accepts it, so perhaps it's a GCC bug?
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A reference to T can be initialized with an object of type T , a function of type T , or an object implicitly convertible to T . Once initialized, a reference cannot be changed to refer to another object.
Uniform Initialization in C++ The uniform initialization is a feature that permits the usage of a consistent syntax to initialize variables and objects which are ranging from primitive type to aggregates. In other words, it introduces brace-initialization that applies braces ({}) to enclose initializer values.
Initializer List is used in initializing the data members of a class. The list of members to be initialized is indicated with constructor as a comma-separated list followed by a colon. Following is an example that uses the initializer list to initialize x and y of Point class.
As mentioned above, in Python, you can easily add and remove elements from a list, so in most cases, it is not necessary to initialize the list in advance. If you want to initialize a list of any number of elements where all elements are filled with any values, you can use the * operator as follows.
Yes, its a bug. This is something new and was voted in the working paper in February 2012 (link).
Nicol Bolas makes a good point in that gcc is actually the conforming compiler according to the FDIS approved C++11 standard because the changes to the working paper were made after that.
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