This program is written in VC++ 6.0 on a WindowsXP machine.
If I try to set an __int64 variable to -2500000000 directly, it is truncated to a 32bit value and the two's complement is taken.
__int64 testval;
testval = -2500000000;
At this point testval equals 1794967293 (110 1010 1111 1101 0000 0111 0000 0000 binary).
When I set the variable to 2500000000 and then multiply by negative one, it works:
__int64 testval;
testval = 2500000000;
testval *= -1;
The variable testval equals -2500000000 (1001 0101 0000 0010 1111 1001 0000 0000 binary).
Any ideas? Thanks.
Get a newer compiler. VC6 standard compliance is VERY poor.
In VC6, try a suffix of i64
, as in
__int64 toobig = -2500000000i64;
Found the documentation!
The compiler is treating the constant 2500000000 as a 32-bit number. You need to explicitly tell it to treat it as a long int
by appending an LL
to the end of the constant. So, try instead:
testval = -2500000000LL;
Update: Since your compiler doesn't support this, and you are stuck with VC6, try instead breaking it into a value that results from the product of two 32 bit numbers as in:
testval = -250000;
testval *= 10000;
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