I know that we have to use a null character to terminate a string array like this:
char str[5] = { 'A','N','S','\0' };
But I just wanted to know why is it essential to use a null character to terminate an array like this?
Also why don't we add a null charater to terminate these :-
char str1[5]="ANS";
The NULL-termination is what differentiates a char array from a string (a NULL-terminated char-array) in C. Most string-manipulating functions relies on NULL to know when the string is finished (and its job is done), and won't work with simple char-array (eg. they'll keep on working past the boundaries of the array, and continue until it finds a NULL somewhere in memory - often corrupting memory as it goes).
In C, 0 (the integer value) is considered boolean FALSE - all other values are considered TRUE. if, for and while uses 0 (FALSE) or non-zero (TRUE) to determent how to branch or if to loop. char is an integer type, an the NULL-character (\0) is actually and simply a char with the decimal integer value 0 - ie. FALSE. This make it very simple to make functions for things like manipulating or copying strings, as they can safely loop as long as the character it's working on is non-zero (ie. TRUE) and stop when it encounters the NULL-character (ie. FALSE) - as this signifies the end of the string. It makes very simple loops, since we don't have to compare, we just need to know if it's 0 (FALSE) or not (TRUE).
Example:
char source[]="Test"; // Actually: T e s t \0 ('\0' is the NULL-character) char dest[8]; int i=0; char curr; do { curr = source[i]; dest[i] = curr; i++; } while(curr); //Will loop as long as condition is TRUE, ie. non-zero, all chars but NULL.
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