I have a NSTableView , i want to get the value present in the cell. I am having only one column so , i just need the row number
i can use this [tableView selectedRow]- but where do i put this i want to put this in a method that gets called on selection of any of the rows.
-(void)tableViewSelectionDidChange:(NSNotification *)notification{
NSLog(@"%d",[tableViewController selectedRow]);
}
The above method also does not work i am getting the error -[NSScrollView selectedRow]: unrecognized selector sent to instance 0x100438ef0]
i want something like the method available in the iPhone tableview-
-(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {
}
In Swift 5.4:
Just use tableView.action = #selector(YOUR_METHOD)
, then in your method, try to do something with tableView.selectedRow
.
This would simply do the trick. Take a look at the demo below:
override func viewDidLoad() {
super.viewDidLoad()
// Do view setup here.
tableView.action = #selector(didSelectRow)
}
@objc private func didSelectRow() {
print("Selected row at \(tableView.selectedRow)")
}
But please be aware that if nothing is selected, or you clicked outside of a cell, then you'll get a tableView.selectedRow
of -1. So you might wanna check if the index is out of range before you use it. :)
What is tableViewController
object? Only NSTableView
instances respond to selectedRow
. You can get current table view (the one that sent the notification) from notification
's object property:
Objective-C:
-(void)tableViewSelectionDidChange:(NSNotification *)notification{
NSLog(@"%d",[[notification object] selectedRow]);
}
Swift:
func tableViewSelectionDidChange(notification: NSNotification) {
let table = notification.object as! NSTableView
print(table.selectedRow);
}
my 2 cents for Xcode 10/swift 4.2
func tableViewSelectionDidChange(_ notification: Notification) {
guard let table = notification.object as? NSTableView else {
return
}
let row = table.selectedRow
print(row)
}
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