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Which constructor will be called when registering services in ConfigureServices

If I have two constructors for a class, how does the service container choose which one to use when I'm registering that service in ConfigureServices?

So lets say I have a class called MyClass with a corresponding interface IMyClass. In the ConfigureServices() method I call the following line of code

services.AddScoped<IMyClass, MyClass>();

How does it choose which constructor to use if I have the following constructors?

MyClass(ILogger logger)

MyClass(ILogger logger, IConfguration configuration)
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user3236794 Avatar asked Dec 13 '19 04:12

user3236794


1 Answers

The constructor matching is performed by a method called CallSiteFactory:CreateConstructorCallSite. Based on its source code, the algorithm is the following:

  • Find all public constructors of the target type
    • If there's none, throw an exception
    • If there's only one, use it
  • Sort all constructors by their number of arguments (ctors with most arguments first)
    • Select the one with the most number of parameters that can be injected by DI
    • If there are multiple such ctors, throw an exception
  • If there are no constructor that can be used, throw an exception

To clarify when there can be an ambiguity, consider these ctors:

MyClass(ILogger logger)
MyClass(IConfguration configuration)

The DI engine can't decide which one to use, because both have valid parameters that can be injected.

In the following case however, there's no ambiguity because the int type isn't registered in the DI engine, and thus can't be injected via DI, and thus the first ctor will be chosen:

MyClass(ILogger logger)
MyClass(int i)

So to answer your question: in your case, the second constructor will be used.

like image 121
Métoule Avatar answered Oct 22 '22 09:10

Métoule