Consider the following MWE:
#include <Python.h>
#include <stdio.h>
int main(void) {
printf("Test 1\n");
Py_Initialize();
printf("Test 2\n");
PyRun_SimpleString("print('Test 3')");
printf("Test 4\n");
return 0;
}
When I compile and run this as normal i get the expected output:
$ ./test
Test 1
Test 2
Test 3
Test 4
But when I redirect the output I get nothing from the python code:
$ ./test | cat
Test 1
Test 2
Test 4
What is happening? And more importantly how do I get my python output written to stdout like expected?
print() and Standard Out. Every running program has a text output area called "standard out", or sometimes just "stdout". The Python print() function takes in python data such as ints and strings, and prints those values to standard out.
A built-in file object that is analogous to the interpreter's standard output stream in Python. stdout is used to display output directly to the screen console. Output can be of any form, it can be output from a print statement, an expression statement, and even a prompt direct for input.
In IDLE, sys. __stdout__ is the program's original standard output - which goes nowhere, since it's not a console application. In other words, IDLE itself has already replaced sys. stdout with something else (its own console window), so you're taking two steps backwards by replacing your own stdout with __stdout__ .
When stdout
refers to a terminal, the output is line buffered otherwise which is block or fully buffered, won't output until the block is full.
To make the output line buffered when stdout
refers to non-terminal, set the mode with setvbuf
And you have to call Py_Finalize()
to have libpython
close its I/O handle.
#include <Python.h>
#include <stdio.h>
int
main(int argc, char **argv) {
//setlinebuf(stdout);
setvbuf(stdout, NULL, _IOLBF, 0);
printf("Test 1\n");
Py_Initialize();
printf("Test 2\n");
PyRun_SimpleString("print('Test 3')");
Py_Finalize();
printf("Test 4\n");
return 0;
}
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