... where count(col) > 1

Question

I have a table like this:

+-----+-----+-------+ | id  | fk  | value | +-----+-----+-------+ | 0   | 1   | peter | | 1   | 1   | josh  | | 3   | 2   | marc  | | ... | ... | ...   | 

I'd like now to get all entries which have more than one value. The expected result would be:

+-----+-------+ | fk  | count | +-----+-------+ | 1   | 2     | | ... | ...   | 

I tried to achieve that like this:

select fk, count(value) from table where count(value) > 1; 

But Oracle didn't like it.

So I tried this...

select * from (     select fk, count(value) as cnt from table ) where cnt > 1; 

...with no success.

Any ideas?

Answer 1

Use the having clause for comparing aggregates.

Also, you need to group by what you're aggregating against for the query to work correctly. The following is a start, but since you're missing a group by clause still it won't quite work. What exactly are you trying to count?

select fk, count(value)  from table  group by fk having count(value) > 1;