I'm learning racket and I have a question about when to use define
and when to use let
.
I have this function:
(define my-function
(lambda (param1 param2 list1)
(/
(count
(lambda (x)
(define a (param1 (remove x list1)))
(define b (drop-right x 1))
(define c (param2 a x-sin-clase))
(eq? (last x) (last c)))
(cdr list1))
(length (cdr list1)))))
Without knowing what the above function does. Is it correct to use define
inside the function body?
I have read somewhere that define
is used to declare global variables and let
is used to declare local variables. I've look in racket's documentation but it doesn't talk about any difference.
Local Binding: let, let*, letrec, ... in The Racket Reference also documents let. A let form binds a set of identifiers, each to the result of some expression, for use in the let body: (let ([id expr] ...) body ...+)
In a let expression, the initial values are computed before any of the variables become bound; in a let* expression, the bindings and evaluations are performed sequentially; while in a letrec expression, all the bindings are in effect while their initial values are being computed, thus allowing mutually recursive ...
In Scheme, you can use local variables pretty much the way you do in most languages. When you enter a let expression, the let variables will be bound and initialized with values. When you exit the let expression, those bindings will disappear.
The let expression is a special form in Lisp that you will need to use in most function definitions. let is used to attach or bind a symbol to a value in such a way that the Lisp interpreter will not confuse the variable with a variable of the same name that is not part of the function.
One difference: Internal defines are in a mutually recursive scope, but let bindings are not.
This means than in a let
:
(let ([x expr-1] [y expr-2])
body)
The expr-1
and expr-2
cannot refer to x
or y
. More concretely,
(let ([x (stream-cons 1 y)] [y (stream-cons 2 x)])
x)
;error=> y: unbound identifier in: y
And if x
or y
is defined outside of the let
, expr-1 and expr-2 will refer to the outer definitions, and not the ones introduced by the let. Concretely:
(define x 'outer)
(let ([x 'inner] [y x]) ; <- this x refers to outer,
y) ; so y is 'outer
;=> 'outer
However, internal defines have a mutually recursive scope, which means that in
(block
(define x expr-1)
(define y expr-2)
body)
The expr-1
and expr-2
can refer to x
or y
. Concretely,
(require racket/block)
(block
(define x (stream-cons 1 y))
(define y (stream-cons 2 x))
(stream->list (stream-take x 5)))
;=> (list 1 2 1 2 1)
define
....A....
(define (f)
(define t1 ..B..)
(define x ..C..)
(define t2 ..D..)
....E....)
....F....
The x
is visible everywhere in the body of f
, but not outside that. That means it's visible in B
, C
, D
, and E
, but not in A or F.
let
....A....
(define (f)
(let ([t1 ..B..]
[x ..C..]
[t2 ..D..])
....E....))
....F....
Here the x
is visible everywhere in the body of the let
, but not outside that. That means it's visible in E
, but not in A, B, C, D, or F.
let*
....A....
(define (f)
(let* ([t1 ..B..]
[x ..C..]
[t2 ..D..])
....E....))
....F....
Here the x
is visible everywhere in the body of the let*
and in let*
bindings that come after it, but not outside that. That means it's visible in D
and E
, but not in A, B, C, or F.
letrec
....A....
(define (f)
(letrec ([t1 ..B..]
[x ..C..]
[t2 ..D..])
....E....))
....F....
The x
is visible everywhere in the body of the letrec
and in the bindings of the letrec
, but not outside that. That means it's visible in B
, C
, D
, and E
, but not in A or F.
The scope of variables in letrec
and the scope of local define
variables are very similar because both letrec
and define
work with mutually recursive scopes.
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