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As one may know, an object just allocated by the new bytecode is not initialized, and is thus not a java.lang.Object. If I do runtime bytecode manipulation and give that object to a method, the JVM will complain or even crash (because the "thing" I gave it is not a java.lang.Object).
So, my question is, when are objects "fully" initialized, i.e. become a java.lang.Object? Is that when the constructor (<init>):
java.lang.Object.<init>? 
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Instantiation: The new keyword is a Java operator that creates the object. Initialization: The new operator is followed by a call to a constructor, which initializes the new object.
1) Object and Class Example: Initialization through reference. Initializing an object means storing data into the object. Let's see a simple example where we are going to initialize the object through a reference variable. We can also create multiple objects and store information in it through reference variable.
Initialization: Initialization is when we put a value in a variable, this happens while we declare a variable. Example: int x = 7; , String myName = "Emi"; , Boolean myCondition = false; Assignment: Assignment is when we already declared or initialized a variable, and we are changing the value.
From the perspective of any given <init> method, the this value is considered initialized after the call to invokespecial returns, whether that is calling another <init> method in the same class or a superclass.
Likewise, for objects created with the new instruction, they are considered initialized once you invokespecial an <init> method on them.
Note that initialization tracking is local to a method. Bytecode verification is done on a method by method basis and each method only sees the objects that are created within it and the calls to methods. The fact that it is impossible to initialize the this value in a constructor without calling another constructor ensures that it will eventually chain up to a java.lang.Object constructor unless it throws or goes into an infinite loop.
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