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when i use Java 8 Stream.of primitive type, the result is confused

    byte[] a = {1,2,3};
    System.out.println(Stream.of(a).count());

    Byte[] b = {1,2,3};
    System.out.println(Stream.of(b).count());

the result is 1 and 3, why?

like image 909
yi jiang Avatar asked Dec 19 '22 12:12

yi jiang


1 Answers

Stream.of only accepts Objects as its arguments. A byte isn't an Object, but a byte array is. If a is an array of byte, then Stream.of(a) can only mean "stream of this one object, which is an array".

If you have a Byte[] array, then each element of the array is an object, so the compiler can guess that's what you mean.

There is information here about how you can stream a byte array: In Java 8, is there a ByteStream class?

like image 196
khelwood Avatar answered Mar 09 '23 00:03

khelwood