Local variables defined outside of a thread seem to be visible from inside so that the following two uses of Thread.new
seem to be the same:
a = :foo
Thread.new{puts a} # => :foo
Thread.new(a){|a| puts a} # => :foo
The document gives the example:
arr = []
a, b, c = 1, 2, 3
Thread.new(a,b,c){|d, e, f| arr << d << e << f}.join
arr #=> [1, 2, 3]
but since a
, b
, c
are visible from inside of the created thread, this should also be the same as:
arr = []
a, b, c = 1, 2, 3
Thread.new{d, e, f = a, b, c; arr << d << e << f}.join
arr #=> [1, 2, 3]
Is there any difference? When do you need to pass local variables as arguments to Thread.new
?
You can only pass a single argument to the function that you are calling in the new thread. Create a struct to hold both of the values and send the address of the struct.
The first way we can send a parameter to a thread is simply providing it to our Runnable or Callable in their constructor.
The last parameter of pthread_create() is passed as the argument to the function, whereas the return value is passed using pthread_exit() and pthread_join() .
When you pass a variable into a thread like that, then the thread makes a local copy of the variable and uses it, so modifications to it do not affect the variable outside of the thread you passed in
a = "foo"
Thread.new{ a = "new"}
p a # => "new"
Thread.new(a){|d| d = "old"}
p a # => "new"
p d # => undefined
I think I hit the actual problem. With a code like this:
sock = Socket.unix_server_socket(SOCK)
sock.listen 10
while conn = sock.accept do
io, address = conn
STDERR.puts "#{io.fileno}: Accepted connection from '#{address}'"
Thread.new{ serve io }
end
it appears to work when accepting few connections. The problem comes when accepting connections quickly one after another. The update to local variable io will be reflected in multiple concurrent threads unless passed as argument to Thread.new
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