As groovy doesn't have EOL marker (such as ;
) it gets confused if you put the operator on the following line
This would work instead:
def a = "test" +
"test" +
"test"
as the Groovy parser knows to expect something on the following line
Groovy sees your original def
as three separate statements. The first assigns test
to a
, the second two try to make "test"
positive (and this is where it fails)
With the new String
constructor method, the Groovy parser is still in the constructor (as the brace hasn't yet closed), so it can logically join the three lines together into a single statement
For true multi-line Strings, you can also use the triple quote:
def a = """test
test
test"""
Will create a String with test on three lines
Also, you can make it neater by:
def a = """test
|test
|test""".stripMargin()
the stripMargin
method will trim the left (up to and including the |
char) from each line
Similar to stripMargin()
, you could also use stripIndent() like
def a = """\
test
test
test""".stripIndent()
Because of
The line with the least number of leading spaces determines the number to remove.
you need to also indent the first "test" and not put it directly after the inital """
(the \
ensures the multi-line string does not start with a newline).
You can tell Groovy that the statement should evaluate past the line ending by adding a pair of parentheses ( ... )
def a = ("test"
+ "test"
+ "test")
A second option is to use a backslash, \
, at the end of each line:
def a = "test" \
+ "test" \
+ "test"
FWIW, this is identical to how Python multi-line statements work.
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