What's the syntax for declaring an array of function pointers without using a separate typedef?

Question

Arrays of function pointers can be created like so:

typedef void(*FunctionPointer)(); FunctionPointer functionPointers[] = {/* Stuff here */}; 

What is the syntax for creating a function pointer array without using the typedef?

Answer 1

arr    //arr  arr [] //is an array (so index it) * arr [] //of pointers (so dereference them) (* arr [])() //to functions taking nothing (so call them with ()) void (* arr [])() //returning void  

so your answer is

void (* arr [])() = {}; 

But naturally, this is a bad practice, just use typedefs :)

Extra: Wonder how to declare an array of 3 pointers to functions taking int and returning a pointer to an array of 4 pointers to functions taking double and returning char? (how cool is that, huh? :))

arr //arr arr [3] //is an array of 3 (index it) * arr [3] //pointers (* arr [3])(int) //to functions taking int (call it) and *(* arr [3])(int) //returning a pointer (dereference it) (*(* arr [3])(int))[4] //to an array of 4 *(*(* arr [3])(int))[4] //pointers (*(*(* arr [3])(int))[4])(double) //to functions taking double and char  (*(*(* arr [3])(int))[4])(double) //returning char 

:))