In C#, what's the difference between
Assert.AreNotEqual
and
Assert.AreNotSame
It means that AreSame() checks that they are the exact same object - if reference indicate the same object in memory. AreEqual() checks that objects has equal type and value. Equal objects can exist in two different places in memory.
AreEqual(Object, Object, String, Object[])Tests whether the specified objects are equal and throws an exception if the two objects are not equal. Different numeric types are treated as unequal even if the logical values are equal. 42L is not equal to 42.
Almost all the answers given here are correct, but it's probably worth giving an example:
public static string GetSecondWord(string text) { // Yes, an appalling implementation... return text.Split(' ')[1]; } string expected = "world"; string actual = GetSecondWord("hello world"); // Good: the two strings should be *equal* as they have the same contents Assert.AreEqual(expected, actual); // Bad: the two string *references* won't be the same Assert.AreSame(expected, actual);
AreNotEqual
and AreNotSame
are just inversions of AreEqual
and AreSame
of course.
EDIT: A rebuttal to the currently accepted answer...
If you use Assert.AreSame
with value types, they are boxed. In other words, it's equivalent to doing:
int firstNumber = 1; int secondNumber = 1; object boxedFirstNumber = firstNumber; object boxedSecondNumber = secondNumber; // There are overloads for AreEqual for various value types // (assuming NUnit here) Assert.AreEqual(firstNumber, secondNumber); // ... but not for AreSame, as it's not intended for use with value types Assert.AreSame(boxedFirstNumber, boxedSecondNumber);
Neither firstNumber
nor secondNumber
has an object value, because int
is a value type. The reason the AreSame
call will fail is because in .NET, boxing a value creates a new box each time. (In Java it sometimes doesn't - this has caught me out before.)
Basically you should never use AreSame
when comparing value types. When you're comparing reference types, use AreSame
if you want to check for identical references; use AreEqual
to check for equivalence under Equals
. EDIT: Note that there are situations where NUnit doesn't just use Equals
directly; it has built-in support for collections, where the elements in the collections are tested for equality.
The claim in the answer that:
Using the example above changing the int to string, AreSame and AreEqual will return the same value.
entirely depends on how the variables are initialized. If they use string literals, then yes, interning will take care of that. If, however, you use:
string firstString = 1.ToString(); string secondString = 1.ToString();
then AreSame
and AreEqual
will almost certainly not return the same value.
As for:
The general rule of thumb is to use AreEqual on value types and AreSame on reference types.
I almost never want to check for reference identity. It's rarely useful to me. I want to check for equivalence which is what AreEqual
checks for. (I'm not saying that AreSame
shouldn't be there - it's a useful method, just far more rarely than AreEqual
.)
Two things can be equal, but different objects. AreNotEqual checks the objects values via the equality test, while AreNotSame checks that they are not the same exact object.
It is obvious why we would want to test that things AreNotEqual (we care about the values being tested); what about AreNotSame? The usefulness of this in testing is found when you have passed references around and want to make sure that after your shuffling is done that two references are still the same object.
In a real world case, we use a lot of caching objects to mitigate round trips to the database. After an object has been handed off to the cache system, our unit tests ensure that in some cases we get back the same object (cache was valid) and in other cases we get back a fresh object (cache was invalidated). Note that AreNotEqual would not necessary suffice in this case. If the object had a new timestamp in the database, yet the data was not "different enough" to fail an equality test, AreNotEqual wouldn't notice that we refreshed the object.
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