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What should the default constructor do in a RAII class with move semantics?

Move semantics are great for RAII classes. They allow one to program as if one had value semantics without the cost of heavy copies. A great example of this is returning std::vector from a function. Programming with value semantics however means, that one would expect types to behave like primitive data types. Those two aspects sometimes seem to be at odds.

On the one hand, in RAII one would expect the default constructor to return a fully initialized object or throw an exception if the resource acquisition failed. This guarantees that any constructed object will be in a valid and consistent state (i.e. safe to use).

On the other hand, with move semantics there exists a point when objects are in a valid but unspecified state. Similarly, primitive data types can be in an uninitialized state. Therefore, with value semantics, I would expect the default constructor to create an object in this valid but unspecified state, so that the following code would have the expected behavior:

// Primitive Data Type, Value Semantics
int i;
i = 5;

// RAII Class, Move Semantics
Resource r;
r = Resource{/*...*/}

In both cases, I would expect the "heavy" initialization to occur only once. I am wondering, what is the best practice regarding this? Obviously, there is a slight practical issue with the second approach: If the default constructor creates objects in the unspecified state, how would one write a constructor that does acquire a resource, but takes no additional parameters? (Tag dispatching comes to mind...)

Edit: Some of the answers have questioned the rationale of trying to make your classes work like primitive data types. Some of my motivation comes from Alexander Stepanov's Efficient Programming with Components, where he talks about regular types. In particular, let me quote:

Whatever is a natural idiomatic expression in c [for built-in types], should be a natural idiomatic expression for regular types.

He goes on to provide almost the same example as above. Is his point not valid in this context? Am I understanding it wrong?

Edit: As there hasn't been much discussion, I am about to accept the highest voted answer. Initializing objects in a "moved-from like" state in the default constructor is probably not a good idea, since everyone who agreed with the existing answers would not expect that behavior.

like image 451
kloffy Avatar asked Aug 11 '13 04:08

kloffy


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What does a default move constructor do?

A move constructor enables the resources owned by an rvalue object to be moved into an lvalue without copying. For more information about move semantics, see Rvalue Reference Declarator: &&. This topic builds upon the following C++ class, MemoryBlock , which manages a memory buffer.

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1 Answers

Programming with value semantics however means, that one would expect types to behave like primitive data types.

Keyword "like". Not "identically to".

Therefore, with value semantics, I would expect the default constructor to create an object in this valid but unspecified state

I really don't see why you should expect that. It doesn't seem like a very desirable feature to me.

what is the best practice regarding this?

Forget this idea that a non POD class should share this feature in common with primitive data types. It's wrong headed. If there is no sensible way to initialize a class without parameters, then that class should not have a default constructor.

If you want to declare an object, but hold off on initializing it (perhaps in a deeper scope), then use std::unique_ptr.

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Benjamin Lindley Avatar answered Nov 15 '22 13:11

Benjamin Lindley