Following code is throwing compile time exception
Type mismatch: cannot convert from Integer to K
What I understand is K
should handle any value that extends Number
.
public <K extends Number> K getValue(){
Integer a = new Integer(1);
return a;//Type mismatch: cannot convert from Integer to K
}
(Note: This is just a test code to put my question without giving irrelevant details of my actual scenario.)
1. Duplicate code makes your program lengthy and bulky : Many programmers feel that if the software is working properly there is no reason to fix code duplications. You forget that you are just un-necessarily making your software bulky.
Having to change the same code multiple times harms your cycle time. If you have to apply a change in multiple places, then implementing that change will take longer. If the duplication is pervasive enough, it'll lead to a decreased delivery speed.
👬 1 - Code Duplication This code smell occurs when there are identical or very similar pieces of code in more than one location. There's also more subtle duplication when specific parts of code look different but perform the same job.
The main problem is that Java doesn't actually have generics at runtime. It's a compile time feature. When you create a generic class in Java they use a method called "Type Erasure" to actually remove all of the generic types from the class and essentially replace them with Object.
The problem here is the fact that K
is a type that extends Number
but it is an unknown sub class of Number
that is why the compiler raises this error because Integer
is only one specific sub class of Number
so it cannot match with any potential target types.
Let's say that you want to cast it explicitly to make it compile with
public <K extends Number> K getValue(){
Integer a = new Integer(1);
return (K) a;
}
Then if you call it expecting any sub class of Number
except Integer
you will get a ClassCastException
, that is exactly what the compiler wants to avoid:
Double d = getValue(); <-- throws ClassCastException
As workaround you could define your method using Number
as returned type as next:
public Number getValue() {
return new Integer(1);
}
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