In the code below:
template<typename T>
struct X {};
int main()
{
X<int()> x; // what is the type of T ?
}
What is the type of T? I saw something like this in the boost
sources.
Psychology A personality type that takes risks; type Ts tend to be extroverted and creative, and crave novel experiences and excitement. See Extreme sports, Novelty seeking behavior.
keyof T returns a union of string literal types. The extends keyword is used to apply constraints to K , so that K is one of the string literal types only. extends means “is assignable” instead of “inherits”; K extends keyof T means that any value of type K can be assigned to the string literal union types.
The t-test, also known as t-statistic or sometimes t-distribution, is a popular statistical tool used to test differences between the means (averages) of two groups, or the difference between one group's mean and a standard value.
The calculations behind t-values compare your sample mean(s) to the null hypothesis and incorporates both the sample size and the variability in the data. A t-value of 0 indicates that the sample results exactly equal the null hypothesis.
Consider the function int func()
. It has a function type int(void)
. It can be implicitly converted to pointer type as the C++ Standard says in 4.3/1, but it this case there's no need in such conversion, so T
has the function type int(void)
, not a pointer to it.
Here is what I did. Though the output of code below is implementation specific, many times it gives a good hint into the type of T that we are dealing with.
template<typename T>
struct X {
X(){
cout << typeid(T).name();
}
};
int main()
{
X<int()> x; // what is the type of T ?
cout << typeid(int()).name() << endl;
}
The output on VC++ is
int __cdecl(void)
int __cdecl(void)
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