Menu
What would this statement yield?
void *p = malloc(sizeof(void)); Edit: An extension to the question.
If sizeof(void) yields 1 in GCC compiler, then 1 byte of memory is allocated and the pointer p points to that byte and would p++ be incremented to 0x2346? Suppose p was 0x2345. I am talking about p and not *p.
583
It's capable of storing at least −9,223,372,036,854,775,807 to 9,223,372,036,854,775,807. Alternatively, get even more overkill with unsigned long long , which will give you at least 0 to 18,446,744,073,709,551,615.
How much bytes of memory does void occupy? void does not occupy any memory. Hence, it takes 0 bytes of memory.
The void pointer in C is a pointer that is not associated with any data types. It points to some data location in the storage. This means that it points to the address of variables. It is also called the general purpose pointer. In C, malloc() and calloc() functions return void * or generic pointers.
void data type. A data type that has no values or operators and is used to represent nothing.
The type void has no size; that would be a compilation error. For the same reason you can't do something like:
void n; EDIT. To my surprise, doing sizeof(void) actually does compile in GNU C:
$ echo 'int main() { printf("%d", sizeof(void)); }' | gcc -xc -w - && ./a.out 1 However, in C++ it does not:
$ echo 'int main() { printf("%d", sizeof(void)); }' | gcc -xc++ -w - && ./a.out <stdin>: In function 'int main()': <stdin>:1: error: invalid application of 'sizeof' to a void type <stdin>:1: error: 'printf' was not declared in this scope If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
