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What is the replacement for isDigit() for characters in Swift?

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swift

As mentioned in this post, before Xcode 6 Beta 4, one could use c.isDigit() and c.isAlpha() to find if c : Character was a digit or alpha. The post mentions that this was removed as it was only effective for ASCII characters.

My question is, what's the replacement? Short of setting up a function with a switch statement for alphanumeric options, how can I test a character on its digit-ness?

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Alex Mitchell Avatar asked Oct 14 '14 02:10

Alex Mitchell


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2 Answers

The "problem" is that a Swift character does not directly correspond to a Unicode code point, but represents an "extended grapheme cluster" which can consist of multiple Unicode scalars. For example

let c : Character = "🇺🇸" // REGIONAL INDICATOR SYMBOL LETTERS US 

is actually a sequence of two Unicode scalars.

If we ignore this fact then you can retrieve the initial Unicode scalar of the character (compare How can I get the Unicode code point(s) of a Character?) and test its membership in a character set:

let c : Character = "5"  let s = String(c).unicodeScalars let uni = s[s.startIndex]  let digits = NSCharacterSet.decimalDigitCharacterSet() let isADigit = digits.longCharacterIsMember(uni.value) 

This returns "true" for the characters "0" ... "9", but actually for all Unicode scalars of the "decimal digit category", for example:

let c1 : Character = "৯" // BENGALI DIGIT NINE U+09EF let c2 : Character = "𝟙" // MATHEMATICAL DOUBLE-STRUCK DIGIT ONE U+1D7D9 

If you care only for the (ASCII) digits "0" ... "9", then the easiest method is probably:

if c >= "0" && c <= "9" { } 

or, using ranges:

if "0"..."9" ~= c { } 

Update: As of Swift 5 you can check for ASCII digits with

if c.isASCII && c.isNumber { } 

using the “Character properties“ introduced with SE-0221.

This solves also the problem with digits modified by a variation selected U+FE0F, like the Keycap Emoji "1️⃣". (Thanks to Lukas Kukacka for reporting this problem.)

let c: Character = "1️⃣" print(Array(c.unicodeScalars)) // ["1", "\u{FE0F}", "\u{20E3}"] print(c.isASCII && c.isNumber) // false 
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Martin R Avatar answered Nov 08 '22 09:11

Martin R


With Swift 5, according to your needs, you may choose one of the following ways in order to solve you problem.


#1. Using Character's isNumber property

Character has a property called isNumber. isNumber has the following declaration:

var isNumber: Bool { get } 

A Boolean value indicating whether this character represents a number.

The Playground sample codes below show how to check if a character represents a number using isNumber:

let character: Character = "9" print(character.isNumber) // true 
let character: Character = "½" print(character.isNumber) // true 
let character: Character = "④" print(character.isNumber) // true 
let character: Character = "1⃣" print(character.isNumber) // true 
let character: Character = "1️⃣" print(character.isNumber) // true 
let character: Character = "৯" print(character.isNumber) // true 
let character: Character = "𝟙" print(character.isNumber) // true 
let character: Character = "F" print(character.isNumber) // false 

#2. Using Character's isWholeNumber property

If you want to check if a character represents a whole number, you can use Character's isWholeNumber property:

let character: Character = "9" print(character.isWholeNumber) // true 
let character: Character = "½" print(character.isWholeNumber) // false 
let character: Character = "④" print(character.isWholeNumber) // true 
let character: Character = "1⃣" print(character.isWholeNumber) // false 
let character: Character = "1️⃣" print(character.isWholeNumber) // false 
let character: Character = "৯" print(character.isWholeNumber) // true 
let character: Character = "𝟙" print(character.isWholeNumber) // true 
let character: Character = "F" print(character.isWholeNumber) // false 

#3. Using Unicode.Scalar.Properties's generalCategory property and Unicode.GeneralCategory.decimalNumber

The Playground sample codes below show how to check if the first Unicode scalar of a character is a decimal number using generalCategory and Unicode.GeneralCategory.decimalNumber:

let character: Character = "9" let scalar = character.unicodeScalars.first! // DIGIT NINE print(scalar.properties.generalCategory == .decimalNumber) // true 
let character: Character = "½" let scalar = character.unicodeScalars.first! // VULGAR FRACTION ONE HALF print(scalar.properties.generalCategory == .decimalNumber) // false 
let character: Character = "④" let scalar = character.unicodeScalars.first! // CIRCLED DIGIT FOUR print(scalar.properties.generalCategory == .decimalNumber) // false 
let character: Character = "1⃣" let scalar = character.unicodeScalars.first! // DIGIT ONE print(scalar.properties.generalCategory == .decimalNumber) // true 
let character: Character = "1️⃣" let scalar = character.unicodeScalars.first! // DIGIT ONE print(scalar.properties.generalCategory == .decimalNumber) // true 
let character: Character = "৯" let scalar = character.unicodeScalars.first! // BENGALI DIGIT NINE print(scalar.properties.generalCategory == .decimalNumber) // true 
let character: Character = "𝟙" let scalar = character.unicodeScalars.first! // MATHEMATICAL DOUBLE-STRUCK DIGIT ONE print(scalar.properties.generalCategory == .decimalNumber) // true 
let character: Character = "F" let scalar = character.unicodeScalars.first! // LATIN CAPITAL LETTER F print(scalar.properties.generalCategory == .decimalNumber) // false 

#4. Using Unicode.Scalar.Properties's generalCategory property and Unicode.GeneralCategory.otherNumber

Similarly, you can check that the first Unicode scalar of a character corresponds to the category Other_Number in the Unicode Standard using generalCategory and Unicode.GeneralCategory.otherNumber:

let character: Character = "9" let scalar = character.unicodeScalars.first! print(scalar.properties.generalCategory == .otherNumber) // false 
let character: Character = "½" let scalar = character.unicodeScalars.first! print(scalar.properties.generalCategory == .otherNumber) // true 
let character: Character = "④" let scalar = character.unicodeScalars.first! print(scalar.properties.generalCategory == .otherNumber) // true 
let character: Character = "1⃣" let scalar = character.unicodeScalars.first! print(scalar.properties.generalCategory == .otherNumber) // false 
let character: Character = "1️⃣" let scalar = character.unicodeScalars.first! print(scalar.properties.generalCategory == .otherNumber) // false 
let character: Character = "৯" let scalar = character.unicodeScalars.first! print(scalar.properties.generalCategory == .otherNumber) // false 
let character: Character = "𝟙" let scalar = character.unicodeScalars.first! print(scalar.properties.generalCategory == .otherNumber) // false 
let character: Character = "F" let scalar = character.unicodeScalars.first! print(scalar.properties.generalCategory == .otherNumber) // false 

#5. Using CharacterSet's decimalDigits property

As an alternative, you can import Foundation and check if CharacterSet.decimalDigits contains the first Unicode scalar of a character:

import Foundation  let character: Character = "9" let scalar = character.unicodeScalars.first! print(CharacterSet.decimalDigits.contains(scalar)) // true 
import Foundation  let character: Character = "½" let scalar = character.unicodeScalars.first! print(CharacterSet.decimalDigits.contains(scalar)) // false 
import Foundation  let character: Character = "④" let scalar = character.unicodeScalars.first! print(CharacterSet.decimalDigits.contains(scalar)) // false 
import Foundation  let character: Character = "1⃣" let scalar = character.unicodeScalars.first! print(CharacterSet.decimalDigits.contains(scalar)) // true 
import Foundation  let character: Character = "1️⃣" let scalar = character.unicodeScalars.first! print(CharacterSet.decimalDigits.contains(scalar)) // true 
import Foundation  let character: Character = "৯" let scalar = character.unicodeScalars.first! print(CharacterSet.decimalDigits.contains(scalar)) // true 
import Foundation  let character: Character = "𝟙" let scalar = character.unicodeScalars.first! print(CharacterSet.decimalDigits.contains(scalar)) // true 
import Foundation  let character: Character = "F" let scalar = character.unicodeScalars.first! print(CharacterSet.decimalDigits.contains(scalar)) // false 

#6. Using Unicode.Scalar.Properties's numericType

Apple documentation states for numericType:

For scalars that represent a number, numericType is the numeric type of the scalar. For all other scalars, this property is nil.

The sample codes below show the possible numeric type (decimal, digit or numeric) for the first scalar of a given character:

let character: Character = "9" let scalar = character.unicodeScalars.first! print(scalar.properties.numericType) // Optional(Swift.Unicode.NumericType.decimal) 
let character: Character = "½" let scalar = character.unicodeScalars.first! print(scalar.properties.numericType) // Optional(Swift.Unicode.NumericType.numeric) 
let character: Character = "④" let scalar = character.unicodeScalars.first! print(scalar.properties.numericType) // Optional(Swift.Unicode.NumericType.digit) 
let character: Character = "1⃣" let scalar = character.unicodeScalars.first! print(scalar.properties.numericType) // Optional(Swift.Unicode.NumericType.decimal) 
let character: Character = "1️⃣" let scalar = character.unicodeScalars.first! print(scalar.properties.numericType) // Optional(Swift.Unicode.NumericType.decimal) 
let character: Character = "৯" let scalar = character.unicodeScalars.first! print(scalar.properties.numericType) // Optional(Swift.Unicode.NumericType.decimal) 
let character: Character = "𝟙" let scalar = character.unicodeScalars.first! print(scalar.properties.numericType) // Optional(Swift.Unicode.NumericType.decimal) 
let character: Character = "F" let scalar = character.unicodeScalars.first! print(scalar.properties.numericType) // nil 
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Imanou Petit Avatar answered Nov 08 '22 07:11

Imanou Petit