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How can ^\d+$ be improved to disallow 0?
EDIT (Make it more concrete):
Examples to allow:
1
30
111
Examples to disallow:
0
00
-22
It doesn't matter if positive numbers with a leading zero are allowed or not (e.g. 022).
This is for Java JDK Regex implementation.
947
Example: The regex "aa\n" tries to match two consecutive "a"s at the end of a line, inclusive the newline character itself. Example: "a\+" matches "a+" and not a series of one or "a"s. ^ the caret is the anchor for the start of the string, or the negation symbol.
The Difference Between \s and \s+ For example, expression X+ matches one or more X characters. Therefore, the regular expression \s matches a single whitespace character, while \s+ will match one or more whitespace characters.
In this case, [0-9]+ matches one or more digits. A regex may match a portion of the input (i.e., substring) or the entire input. In fact, it could match zero or more substrings of the input (with global modifier). This regex matches any numeric substring (of digits 0 to 9) of the input.
148
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