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What is the purpose and result of using INADDR_ANY?

In Python when we want to make a script that listens for multicast traffic we set the IP_ADD_MEMBERSHIP option of the socket with a value that consists of the multicast group address and the address of a local interface on which it will listen for the group's traffic.

Many examples on the Internet pass to IP_ADD_MEMBERSHIP the INADDR_ANY wildcard address as the local interface, and some of them state that this will make the socket to listen on all interfaces for multicast packets. However the Linux ip(7) man page states that when using INADDR_ANY

"an appropriate interface is chosen by the system"

and the freebsd man page says that it will choose the "default interface".

So either some answers online are wrong, or there's something that I'm missing here. I believe there's a confusion with INADDR_ANY when used as a parameter in IP_ADD_MEMBERSHIP, and INADDR_ANY when used as a parameter in bind() (represented by an empty string) but I'm not really sure. Can someone please clarify what is happening with INADDR_ANY or 0.0.0.0 when used in IP_ADD_MEMBERSHIP (i.e. it chooses the default interface or all interfaces) and if it behaves differently when used with bind?

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AndroidX Avatar asked Sep 06 '17 03:09

AndroidX


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What is the value of Inaddr_any?

There are several special addresses: INADDR_LOOPBACK (127.0. 0.1) always refers to the local host via the loopback device; INADDR_ANY (0.0. 0.0) means any address for binding; INADDR_BROADCAST (255.255. 255.255) means any host and has the same effect on bind as INADDR_ANY for historical reasons.

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This is an IP address that is used when we don't want to bind a socket to any specific IP. Basically, while implementing communication, we need to bind our socket to an IP address. When we don't know the IP address of our machine, we can use the special IP address INADDR_ANY .

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1 Answers

When INADDR_ANY is given as the address in a bind call, this causes the socket to listen on the given port for any network interface.

After calling bind in this way, you'll see an entry like this in the output of the netstat command:

udp        0      0 0.0.0.0:46162           0.0.0.0:*  

This is a UDP socket that was bound to INADDR_ANY with port 46162.

When used as the interface address when setting the IP_ADD_MEMBERSHIP option, INADDR_ANY indicates that the OS will chose an interface to join the given multicast group on, i.e. the "default" network interface.

It does not mean that it will join the group on all interfaces. To do that, you would need to itereate over all network interfaces and set the IP_ADD_MEMBERSHIP option on each one.

I've worked with Linux, Solaris, FreeBSD, and Windows, and none of them joins a multicast group on all interfaces when using INADDR_ANY.

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dbush Avatar answered Sep 18 '22 01:09

dbush