I am contributing Rust code to RosettaCode to both learn Rust and contribute to the Rust community at the same time. What is the best idiomatic way to pop the last n elements in a mutable Vec
?
Here's roughly what I have written but I'm wanting to see if there's a better way:
fn main() {
let mut nums: Vec<u32> = Vec::new();
nums.push(1);
nums.push(2);
nums.push(3);
nums.push(4);
nums.push(5);
let n = 2;
for _ in 0..n {
nums.pop();
}
for e in nums {
println!("{}", e)
}
}
(Playground link)
I'd recommend using Vec::truncate
:
fn main() {
let mut nums = vec![1, 2, 3, 4, 5];
let n = 2;
let final_length = nums.len().saturating_sub(n);
nums.truncate(final_length);
println!("{:?}", nums);
}
Additionally, I
saturating_sub
to handle the case where there aren't N
elements in the vectorvec![]
to construct the vector of numbers easilyNormally when you "pop" something, you want to have those values. If you want the values in another vector, you can use Vec::split_off
:
let tail = nums.split_off(final_length);
If you want access to the elements but do not want to create a whole new vector, you can use Vec::drain
:
for i in nums.drain(final_length..) {
println!("{}", i)
}
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