Given a character c and a number n, how can I create a String that consists of n repetitions of c? Doing it manually is too cumbersome:
StringBuilder sb = new StringBuilder(n); for (int i = 0; i < n; ++i) { sb.append(c); } String result = sb.toString();
Surely there is some static library function that already does this for me?
Common Ways to Build a String We'll iterate through a for loop N times appending the repeated character: StringBuilder builder = new StringBuilder(N); for (int i = 0; i < N; i++) { builder. append("a"); } String newString = builder. toString(); assertEquals(EXPECTED_STRING, newString);
The string can be repeated N number of times, and we can generate a new string that has repetitions. repeat() method is used to return String whose value is the concatenation of given String repeated count times. If the string is empty or the count is zero then the empty string is returned.
We can easily use the Python join() function to create a string of n characters.
int n = 10; char[] chars = new char[n]; Arrays.fill(chars, 'c'); String result = new String(chars);
EDIT:
It's been 9 years since this answer was submitted but it still attracts some attention now and then. In the meantime Java 8 has been introduced with functional programming features. Given a char c
and the desired number of repetitions count
the following one-liner can do the same as above.
String result = IntStream.range(1, count).mapToObj(index -> "" + c).collect(Collectors.joining());
Do note however that it is slower than the array approach. It should hardly matter in any but the most demanding circumstances. Unless it's in some piece of code that will be executed thousands of times per second it won't make much difference. This can also be used with a String instead of a char to repeat it a number of times so it's a bit more flexible. No third-party libraries needed.
If you can, use StringUtils from Apache Commons Lang:
StringUtils.repeat("ab", 3); //"ababab"
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