From the program below or here, why does the last call to System.out.println(i)
print the value 7
?
class PrePostDemo { public static void main(String[] args){ int i = 3; i++; System.out.println(i); // "4" ++i; System.out.println(i); // "5" System.out.println(++i); // "6" System.out.println(i++); // "6" System.out.println(i); // "7" } }
i = 5; System.out.println(++i); //6
This prints out "6" because it takes i, adds one to it, and returns the value: 5+1=6. This is prefixing, adding to the number before using it in the operation.
i = 6; System.out.println(i++); //6 (i = 7, prints 6)
This prints out "6" because it takes i, stores a copy, adds 1 to the variable, and then returns the copy. So you get the value that i was, but also increment it at the same time. Therefore you print out the old value but it gets incremented. The beauty of a postfix increment.
Then when you print out i, it shows the real value of i because it had been incremented: 7.
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