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I don't really understand the difference between the XPath functions name and local-name.
Could you give an example of a situation where they would differ?
Given this example:
<?xml version="1.0" ?> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head></head> </html> I get the same result with these two queries: //*[local-name()="head"] and //*[name()="head"]. Why is that?
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So applying the local-name() function to this node returns author . When a node has no expanded name, such as author , applying the local-name() function on this node returns the node name as is, i.e., author . If the node-set argument is omitted, it defaults to a node-set with the context node as its only member.
The local-name function returns a string representing the local name of the first node in a given node-set.
The name of the current node with the prefix removed. For example, LocalName is book for the element <bk:book>.
With the XML being
<x:html xmlns:x="http://www.w3.org/1999/xhtml"/> the stylesheet
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output indent="yes"/> <xsl:template match="*"> <local-name><xsl:value-of select="local-name()"/></local-name> <name><xsl:value-of select="name()"/></name> </xsl:template> </xsl:stylesheet> outputs
<local-name>html</local-name> <name>x:html</name> So the local-name() result is without any prefix, the name() result might include a prefix.
In your sample with a default namespace declaration no prefix is present, therefore name() and local-name() give the same result.
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