What is the correct way to get a subarray in Scala?

Question

I am trying to get a subarray in scala, and I am a little confused on what the proper way of doing it is. What I would like the most would be something like how you can do it in python:

x = [3, 2, 1] x[0:2] 

but I am fairly certain you cannot do this.

The most obvious way to do it would be to use the Java Arrays util library.

import java.util.Arrays val start = Array(1, 2, 3) Arrays.copyOfRange(start, 0, 2) 

But it always makes me feel a little dirty to use Java libraries in Scala. The most "scalaic" way I found to do it would be

def main(args: List[String]) {     val start = Array(1, 2, 3)     arrayCopy(start, 0, 2) } def arrayCopy[A](arr: Array[A], start: Int, end: Int)(implicit manifest: Manifest[A]): Array[A] = {     val ret = new Array(end - start)     Array.copy(arr, start, ret, 0, end - start)     ret } 

but is there a better way?

Answer 1

You can call the slice method:

scala> Array("foo", "hoo", "goo", "ioo", "joo").slice(1, 4) res6: Array[java.lang.String] = Array(hoo, goo, ioo) 

It works like in python.