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What is the CMake equivalent to "gcc -fvisibility=hidden" when controlling the exported symbol of a shared library?

I developed cross platform software in c++. As I know, Linux .so exported all the symbols by default, well through "gcc -fvisibility=hidden" I can set all the exported symbols as hidden, then set __attribute__(visibility("default")) for the class and function I want to export, so I can control what I want to export.

My question is, using CMake, how can I do the work as "gcc -fvisibility=hidden" control?

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sailing Avatar asked Jun 13 '13 06:06

sailing


2 Answers

Instead of setting compiler flags directly, you should be using a current CMake version and the <LANG>_VISIBILITY_PRESET properties instead. This way you can avoid compiler specifics in your CMakeLists and improve cross platform applicability (avoiding errors such as supporting GCC and not Clang).

I.e., if you are using C++ you would either call set(CMAKE_CXX_VISIBILITY_PRESET hidden) to set the property globally, or set_target_properties(MyTarget PROPERTIES CXX_VISIBILITY_PRESET hidden) to limit the setting to a specific library or executable target. If you are using C just replace CXX by C in the aforementioned commands. You may also want to investigate the VISIBLITY_INLINES_HIDDEN property as well.

The documentation for GENERATE_EXPORT_HEADER includes some more tips and examples related to both properties.

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Joe Avatar answered Nov 01 '22 03:11

Joe


You can add a flag to the Cmake compiler like that:

set(CMAKE_C_FLAGS "${CMAKE_C_FLAGS} -fvisibility=hidden")

To make sure that this only done under Linux you can use this code:

if(UNIX AND CMAKE_COMPILER_IS_GNUCC)
    set(CMAKE_C_FLAGS "${CMAKE_C_FLAGS} -fvisibility=hidden")
endif()
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tune2fs Avatar answered Nov 01 '22 02:11

tune2fs