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What is the best way to separate double into two parts "integer & fraction" in java

I have tried to separate 5.6 (for example) by the following method:

private static double[] method(double d)
{
    int integerPart = 0;
    double fractionPart = 0.0;
    integerPart = (int) d;
    fractionPart = d - integerPart;
    return new double[]{integerPart, fractionPart};
}

But what I got is:

[0] = 5.0
[1] = 0.5999999999999996

Do you have any suggestion about doing this without converting the number to string?

like image 328
Eng.Fouad Avatar asked May 19 '11 18:05

Eng.Fouad


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2 Answers

Use BigDecimal to do that same calculation. (using doubles has precision problems because of its representation).

  • Construct it with new BigDecimal(String.valueOf(yourDouble)) (this is still going through string, but the parts are not separated via string manipulation)
  • use bd.subtract(new BigDecimal(bd.intValue()) to determine the fraction
like image 130
Bozho Avatar answered Oct 10 '22 10:10

Bozho


Here is another solution based on BigDecimal (that does not go through a String).

private static double[] method(double d) {
    BigDecimal bd = new BigDecimal(d);
    return new double[] { bd.intValue(),
                          bd.remainder(BigDecimal.ONE).doubleValue() };
}

As you'll note, you still won't get just 0.6 as output for the fractional part. (You can't even store 0.6 in a double!) This is due to the fact that the mathematical, real number, 5.6 is actually not represented by a double exactly as 5.6 but as 5.599999...


You could also do

private static double[] method(double d) {
    BigDecimal bd = BigDecimal.valueOf(d);
    return new double[] { bd.intValue(),
                          bd.remainder(BigDecimal.ONE).doubleValue() };
}

which actually does yield [5.0, 0.6].

The BigDecimal.valueOf is in most JDK's (internally) implemented through a call to Double.toString however. But at least the string-related stuff doesn't clutter your code :-)


Good follow-up question in comment:

If it is represented as 5.599999999..., then why Double.toString(5.6) gives exactly "5.6"

The Double.toString method is actually very sophisticated. From the documentation of Double.toString:

[...]

How many digits must be printed for the fractional part of m or a? There must be at least one digit to represent the fractional part, and beyond that as many, but only as many, more digits as are needed to uniquely distinguish the argument value from adjacent values of type double. That is, suppose that x is the exact mathematical value represented by the decimal representation produced by this method for a finite nonzero argument d. Then d must be the double value nearest to x; or if two double values are equally close to x, then d must be one of them and the least significant bit of the significand of d must be 0.

[...]

The code for getting the characters "5.6" boils down to FloatingDecimal.getChars:

private int getChars(char[] result) {
    assert nDigits <= 19 : nDigits; // generous bound on size of nDigits
    int i = 0;
    if (isNegative) { result[0] = '-'; i = 1; }
    if (isExceptional) {
        System.arraycopy(digits, 0, result, i, nDigits);
        i += nDigits;
    } else {
        if (decExponent > 0 && decExponent < 8) {
            // print digits.digits.
            int charLength = Math.min(nDigits, decExponent);
            System.arraycopy(digits, 0, result, i, charLength);
            i += charLength;
            if (charLength < decExponent) {
                charLength = decExponent-charLength;
                System.arraycopy(zero, 0, result, i, charLength);
                i += charLength;
                result[i++] = '.';
                result[i++] = '0';
            } else {
                result[i++] = '.';
                if (charLength < nDigits) {
                    int t = nDigits - charLength;
                    System.arraycopy(digits, charLength, result, i, t);
                    i += t;
                } else {
                    result[i++] = '0';
                }
            }
        } else if (decExponent <=0 && decExponent > -3) {
            result[i++] = '0';
            result[i++] = '.';
            if (decExponent != 0) {
                System.arraycopy(zero, 0, result, i, -decExponent);
                i -= decExponent;
            }
            System.arraycopy(digits, 0, result, i, nDigits);
            i += nDigits;
        } else {
            result[i++] = digits[0];
            result[i++] = '.';
            if (nDigits > 1) {
                System.arraycopy(digits, 1, result, i, nDigits-1);
                i += nDigits-1;
            } else {
                result[i++] = '0';
            }
            result[i++] = 'E';
            int e;
            if (decExponent <= 0) {
                result[i++] = '-';
                e = -decExponent+1;
            } else {
                e = decExponent-1;
            }
            // decExponent has 1, 2, or 3, digits
            if (e <= 9) {
                result[i++] = (char)(e+'0');
            } else if (e <= 99) {
                result[i++] = (char)(e/10 +'0');
                result[i++] = (char)(e%10 + '0');
            } else {
                result[i++] = (char)(e/100+'0');
                e %= 100;
                result[i++] = (char)(e/10+'0');
                result[i++] = (char)(e%10 + '0');
            }
        }
    }
    return i;
}
like image 43
aioobe Avatar answered Oct 10 '22 12:10

aioobe