What is the best way to repeatedly execute a function every x seconds? [closed]

Question

I want to repeatedly execute a function in Python every 60 seconds forever (just like an NSTimer in Objective C or setTimeout in JS). This code will run as a daemon and is effectively like calling the python script every minute using a cron, but without requiring that to be set up by the user.

In this question about a cron implemented in Python, the solution appears to effectively just sleep() for x seconds. I don't need such advanced functionality so perhaps something like this would work

while True:     # Code executed here     time.sleep(60) 

Are there any foreseeable problems with this code?

Answer 1

If your program doesn't have a event loop already, use the sched module, which implements a general purpose event scheduler.

import sched, time s = sched.scheduler(time.time, time.sleep) def do_something(sc):      print("Doing stuff...")     # do your stuff     s.enter(60, 1, do_something, (sc,))  s.enter(60, 1, do_something, (s,)) s.run() 

If you're already using an event loop library like asyncio, trio, tkinter, PyQt5, gobject, kivy, and many others - just schedule the task using your existing event loop library's methods, instead.

Answer 2

Lock your time loop to the system clock like this:

import time starttime = time.time() while True:     print("tick")     time.sleep(60.0 - ((time.time() - starttime) % 60.0))