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I have a script named test1.py which is not in a module. It just has code that should execute when the script itself is run. There are no functions, classes, methods, etc. I have another script which runs as a service. I want to call test1.py from the script running as a service.
For example:
File test1.py:
print "I am a test" print "see! I do nothing productive." File service.py:
# Lots of stuff here test1.py # do whatever is in test1.py I'm aware of one method which is opening the file, reading the contents, and basically evaluating it. I'm assuming there's a better way of doing this. Or at least I hope so.
565
this: source /path/to/script; Or use a bash command to execute it: /bin/bash /path/to/script; The 1st and 3rd methods execute a script as another process, so variables and functions in another script will not be accessible.
To run Python scripts with the python command, you need to open a command-line and type in the word python , or python3 if you have both versions, followed by the path to your script, just like this: $ python3 hello.py Hello World!
The usual way to do this is something like the following.
test1.py
def some_func(): print 'in test 1, unproductive' if __name__ == '__main__': # test1.py executed as script # do something some_func() service.py
import test1 def service_func(): print 'service func' if __name__ == '__main__': # service.py executed as script # do something service_func() test1.some_func() If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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