I'm reading "Bash Guide for Beginners". It says:
If the first character of
PARAMETER
is an exclamation point, Bash uses the value of the variable formed from the rest ofPARAMETER
as the name of the variable; this variable is then expanded and that value is used in the rest of the substitution, rather than the value ofPARAMETER
itself. This is known as indirect expansion.
The example given is:
franky ~> echo ${!N*} NNTPPORT NNTPSERVER NPX_PLUGIN_PATH
I don't quite understand here:
the value of the variable formed from the rest of
PARAMETER
As the PARAMETER
is just !N*
, then
the rest of
PARAMETER
is just N*
. How could this form a variable? Did Bash search all possible command there?
In the bash shell, ${! var} is a variable indirection. It expands to the value of the variable whose name is kept in $var . The variable expansion ${var+value} is a POSIX expansion that expands to value if the variable var is set (no matter if its value is empty or not).
As you see, it is a way to define "variable variables". That is, to use variables whose content is the name of another variable. From Bash Reference Manual → 3.5.
The roots of Value-at-Risk (VaR) can be traced backed to 1920's when was initially used by the NYSE as a risk measure to impose capital requirements on its members.
Parameter expansion can be used to modify, expand or replace the value of the parameter. The optional braces are used with the variable when using variable parameter expansion, such as 'echo ${myvar}'.
If you read the bash
man page, it basically confirms what you have stated:
If the first character of parameter is an exclamation point (
!
), a level of variable indirection is introduced. Bash uses the value of the variable formed from the rest of parameter as the name of the variable; this variable is then expanded and that value is used in the rest of the substitution, rather than the value of parameter itself. This is known as indirect expansion.
However, reading on from there:
The exceptions to this are the expansions of
${!prefix*}
and${!name[@]}
described below.
${!prefix*}
Names matching prefix. Expands to the names of variables whose names begin with prefix, separated by the first character of theIFS
special variable.
In other words, your particular example ${!N*}
is an exception to the rule you quoted. It does, however, work as advertised in the expected cases, such as:
$ export xyzzy=plugh ; export plugh=cave $ echo ${xyzzy} # normal, xyzzy to plugh plugh $ echo ${!xyzzy} # indirection, xyzzy to plugh to cave cave
There appears to be an exception when the given "indirection" ends in a *
, as it does here. In this case, it gives all variable names that start with the part you specified (N
here). Bash can do that because it tracks variables and knows which ones exist.
True indirection is this:
Say I have a variable $VARIABLE
set to 42
, and I have another variable $NAME
set to VARIABLE
. ${!NAME}
will give me 42
. You use the value of one variable to tell you the name of another:
$ NAME="VARIABLE" $ VARIABLE=42 $ echo ${!NAME} 42
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