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I wrote this code:
float b = 3.6; and I get this:
Error:Unresolved compilation problem: Type mismatch: cannot convert from double to float
Why? Whats the definition of float?
582
asked Feb 22 '11 10:02
A float data type in Java stores a decimal value with 6-7 total digits of precision. So, for example, 12.12345 can be saved as a float, but 12.123456789 can't be saved as a float. When representing a float data type in Java, we should append the letter f to the end of the data type; otherwise it will save as double.
Float is a single-precision value that has a width of 32 bits in storage. On some processors, this single precision is faster and takes less size when compared to the double-precision. This is arguable as on some modern processors, double-precision is faster than the single-precision.
float: The float data type is a single-precision 32-bit IEEE 754 floating point. Its range of values is beyond the scope of this discussion, but is specified in the Floating-Point Types, Formats, and Values section of the Java Language Specification.
Float is a datatype which is used to represent the floating point numbers. It is a 32-bit IEEE 754 single precision floating point number ( 1-bit for the sign, 8-bit for exponent, 23*-bit for the value. It has 6 decimal digits of precision.
In Java, when you type a decimal number as 3.6, its interpreted as a double. double is a 64-bit precision IEEE 754 floating point, while floatis a 32-bit precision IEEE 754 floating point. As a float is less precise than a double, the conversion cannot be performed implicitly.
If you want to create a float, you should end your number with f (i.e.: 3.6f).
For more explanation, see the primitive data types definition of the Java tutorial.
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