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I know it's a Regular Expression. I have seen this particular regular expression in a piece of code. What does it do? Thanks
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\d (digit) matches any single digit (same as [0-9] ). The uppercase counterpart \D (non-digit) matches any single character that is not a digit (same as [^0-9] ). \s (space) matches any single whitespace (same as [ \t\n\r\f] , blank, tab, newline, carriage-return and form-feed).
The RegExp \D Metacharacter in JavaScript is used to search non digit characters i.e all the characters except digits. It is same as [^0-9]. Syntax: /\D/ or new RegExp("\\D") Syntax with modifiers: /\D/g.
Within a regex a \ has a special meaning, e.g. \d means a decimal digit. If you add a backslash in front of the backslash this special meaning gets lost.
For example, \d means a range of digits (0-9), and \w means a word character (any lowercase letter, any uppercase letter, the underscore character, or any digit).
Expanding on minitech's answer:
( start a capture group\d a shorthand character class, which matches all numbers; it is the same as [0-9] + one or more of the expression) end a capture group/ a literal forward slashHere is an example:
>>> import re >>> exp = re.compile('(\d+)/(\d+)') >>> foo = re.match(exp,'1234/5678') >>> foo.groups() ('1234', '5678') If you remove the brackets (), the expression will still match, but you'll only capture one set:
>>> foo = re.match('\d+/(\d+)','1234/5678') >>> foo.groups() ('5678',) It matches one or more digits followed by a slash followed by one or more digits.
The two "one or more digits" here also form groups, which can be extracted and used.
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