I am confused about the example shown in the shapeless feature overview.
object size extends Poly1 {
implicit def caseInt = at[Int](x => 1)
implicit def caseString = at[String](_.length)
implicit def caseTuple[T, U]
(implicit st : Case.Aux[T, Int], su : Case.Aux[U, Int]) =
at[(T, U)](t => size(t._1)+size(t._2))
}
scala> size(((23, "foo"), 13))
res7: Int = 5
Many thanks in advance
More explanations about PolyN
function you can find here: What is "at" in shapeless (scala)?
1 & 2. So let's rewrite this code to make it more clear:
object size extends Poly1 {
implicit def caseInt = at[Int](x => 1)
implicit def caseString = at[String](_.length)
implicit def caseTuple[T, U]
(implicit st : Case.Aux[T, Int], su : Case.Aux[U, Int]) =
at[(T, U)](t => st(t._1) + su(t._2))
}
Case
type class provides us applying some poly function to some object with it's type.
http://xuwei-k.github.io/shapeless-sxr/shapeless-2.10-2.0.0-M1/shapeless/poly.scala.html#shapeless.PolyDefns;Case
Let's try to make some function:
def sizeF[F, S](t: (F, S)) = size(t)
It is impossible, without type class wich defines how to apply function:
def sizeF[F, S](t: (F, S))
(implicit cse: Case[size.type, (F, S) :: HNil]) = size(t)
Case.Aux[T, U]
it is a shortcut for: poly.Case[this.type, T :: HNil]{ type Result = U }
T
- it is an argument, U
- the result type after application.
3. Let's modify function and make avalible application to ((23, "foo", 123), 13)
, we need to add function to work with triples:
object size extends Poly1 {
implicit def caseInt = at[Int](x => 1)
implicit def caseString = at[String](_.length)
implicit def caseTuple[T, U]
(implicit st : Case.Aux[T, Int], su : Case.Aux[U, Int]) =
at[(T, U)](t => size(t._1) + size(t._2))
implicit def caseTriple[T, U, F]
(implicit st : Case.Aux[T, Int], su : Case.Aux[U, Int], sf: Case.Aux[F, Int]) =
at[(T, U, F)](t => size(t._1) + size(t._2) + size(t._3))
}
size(((23, "foo", 123), 13)) //> res0: Int = 6
As expected.
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