Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

What exactly is the need for gamma correction?

I have problems to fully understand the need for gamma correction. I hope you guys can help me.

Let’s assume we want to display 256 neighboring pixels. These pixels should be a smooth gradient from black to white. To denote theirs colors, we use linear gray values from 0..255. Due to the non-linearity of the human eye, the monitor must not just turn these values into linear luminance values. If the neighboring pixels had the luminance values (1/256)*I_max, (2/256)*I_max, et cetera, we would perceive in the darker area too large differences in brightness between two pixels (the gradient would not be smooth).

Fortunately, a monitor has the reciprocal non-linearity to the human eye. That means, if we put linear gray values 0..255 into the frame buffer, then the monitor turns them into non-linear luminance values x^gamma. However, as our eye is non-linear the other way round, we perceive a smooth linear gradient. The non-linearity of the monitor and the one of our eye cancel each other out.

So, why do we need the gamma correction? I have read in books that we always want the monitor to produce linear luminance values. According to them, the non-linearity of the monitor must be compensated before writing the gray values to the frame buffer. That is done by the gamma correction. However, my problem here is that - as far as I understand it - we would not perceive linear brightness values (i.e. we would not perceive a smooth, steady gradient) when the monitor produces linear luminance values.

As far as I see it, it would be just perfect, if we put linear gray values into the frame buffer. The monitor turns these values into non-linear luminance values and our eye perceives linear brightness values again, because the eye is reciprocal non-linear. There would be no need to gamma correct the gray values in the frame buffer and no need to force the monitor to produce linear luminance values.

What is wrong with my way of looking at these things? Thanks

like image 781
user1494080 Avatar asked Oct 19 '12 13:10

user1494080


Video Answer


2 Answers

Allow me to ‘resurrect’ this question since I am struggling with similar questions right now and I think I have found the answer -it may be useful for someone else. Or I might be wrong and someone could tell me :)

I think there is nothing wrong with your way of thinking. Thing is, you don‘t need to gamma-correct all the time, if you know what you are doing. It depends on what you want to achieve. Let‘s see two different cases.

A) Light simulation (AKA rendering). You have a diffuse surface with a light pointing towards it. Then, the light's intensity is doubled.

Well. Let’s see what happens in the real world in such situation. Assuming a purely diffuse surface, the intensity of the light reflected is going to be the surface's albedo multiplied by the incoming light intensity and the cosine of the incoming light angle and the normal. Whatever. Thing is, when the incoming light intensity is doubled, the reflected light intensity will be doubled too. This is why light transport is said to be a linear process. Funny enough, you will not perceive the surface as twice as bright, because our perception is nonlinear (This is modelled by the so-called Steven's power law). Put again: in the real world the reflected light is doubled, but you do not perceive it twice as bright.

Now, how would we simulate this? Well, if we have a sRGB texture with the surface's albedo, we would need to linearlize it (by de-correcting it, which means applying the 2.2 gamma). Now that it is linear, and we have the light intensity, we can use the formula I said before to compute the reflected light intensity. Since we are in a linear space, by doubling the intensity we will double the output, like in the real world. Now we gamma-correct our results. Because of this, when the screen displays the rendered image, it will apply the gamma and so it will have a linear response, meaning that the intensity of the light emited by the screen will be twice as much when we simulate the twice-as-poweful light than when we simulate the first one. So the light that arrive at your eyes from your screen will have double the intensity. Exactly as it would happen if you were looking at the real surface with real lights affecting it. You will not perceive the second render twice as bright, of course but, again, and as we said earlier, this is exactly what it would happen in the real situation. Same behavior in the real world and in the simulation means that the simulation (the render) was correct :)

B) A different case is precisely if you want a gradient that you want to 'look' (AKA being perceived) as linear.

Since you want the nonlinear response of the screen to cancel out our nonlinear visual perception, you can skip gamma correction altogether (as you suggest). Or, more accurately, keep operating in linear space and gamma-correcting, but creating your gradient not with consecutive values for the pixels(1,2,3...255) that would be perceived nonlinearly (because of Steven's), but values transformed by the inverse of our perceptual brightness response (that is, applying an exponent of 1/0.5=2 to the normalized values. This is applying the reciprocal of Steven's exponent for brightness).

As a matter of fact, if you see gamma-corrected linear gradient such as the one in http://scanline.ca/gradients/ you do not perceive it as linear at all: you see far more variation in the lower intensities than in the higher ones (as expected).

Well, at least this is my current understanding of the topic. I hope it helps anyone. And again, please, please, if it is wrong I would be really grateful if someone could point it out...

like image 182
jmeseguerdepaz Avatar answered Oct 12 '22 21:10

jmeseguerdepaz


The problem is really when doing color calculations. For example, if you are blending two colors, you need to use the linear intensities to do the calculations. To actually display the proper result, you then have to convert the linear intensities back to the gamma-corrected intensities.

How your eyes perceive the intensities isn't relevant. To do color calculations correctly, they have to be done based on the physical principles of optics, which relies on linear luminance values. Once you have calculated a color, you want those luminance values to be output by your monitor, regardless of how it is perceived, so you have to compensate for the fact that the monitor doesn't directly produce the colors that you want.

like image 21
Vaughn Cato Avatar answered Oct 12 '22 19:10

Vaughn Cato