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I don't understand why I can't use my variable c.
code:
from turtle import * speed(0) hideturtle() c = 450 def grid(x,y,a): seth(0) pu() goto(x,y) pd() for i in range(4): forward(a) rt(90) for i in range(c/10): seth(0) forward(10) rt(90) forward(c) backward(c) for i in range(c/10): seth(0) rt(90) forward(10) rt(90) forward(c) backward(c) pu() goto(a+10,0) write("x") goto(0,a+10) write("y") pd() grid(0,0,c) grid(-c,0,c) grid(-c,c,c) grid(0,c,c) I get the following error message:
Traceback (most recent call last): File "C:\Users\nick\Desktop\gridv2.py", line 35, in <module> grid(0,0,c) File "C:\Users\nick\Desktop\gridv2.py", line 15, in grid for i in range(c/10): TypeError: 'float' object cannot be interpreted as an integer 
385
The Python "TypeError: 'float' object cannot be interpreted as an integer" occurs when we pass a float to a function that expects an integer argument. To solve the error, use the floor division operator, e.g. for i in range(my_num // 5): .
The Python "TypeError: 'float' object is not iterable" occurs when we try to iterate over a float or pass a float to a built-in function like, list() or tuple() . To solve the error, use the range() built-in function to iterate over a range, e.g. for i in range(int(3.0)): .
The Python "TypeError: 'list' object cannot be interpreted as an integer" occurs when we pass a list to a function that expects an integer argument, e.g. range() . To solve the error, either pass the length of the list, e.g. len(my_list) or pass an integer to the function. Here is an example of how the error occurs.
In:
for i in range(c/10): You're creating a float as a result - to fix this use the int division operator:
for i in range(c // 10): If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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